Perform the following exercise:
Exercise 1.3.2
(Exercise taken from the
PDF:)
Traduccion:
1.3.2 Una urna contiene 6 bolas rojas, 5 bolas verdes y 3 bolas amarillas, 3 bolas sin reemplazo. ¿Cual es la probabilidad de que una bola sea amarilla?.
Solution:
First, we have the color sequence and represent with letters, for example:
Red = R
Green = G
Yellow = Y
We add the balls in total, it is 14, now, we get the chance, we have 3 yellow balls out of 14 balls in total, is as follows:
P ( Y ) = 3/14
We describe the most important events that can happen, to get as many yellow probability on each play we get
P = {YYY, YYR, YRG .....}
We have that on the first play I can get 3 yellow, the second two yellow and one red, one yellow in the third, one red and one green.
We select the three most important events and multimplicamos by probabilities, we have:
And the likelihood is:
We have that the probability of drawing a yellow ball is 3/364 opportunities
Referencias:
- http://www.amazon.com/exec/obidos/ISBN=0849339855